pull down to refresh

Since we aren’t told anything about where the triangles meet, it must not matter.

So, we can do the calculation for two triangles that meet at one of the box corners.

That yields 28.

You are right!

reply

Ok, that was a little more elegant

reply

well that tutor does this for a living. Ofc her solutions are elegant haha

reply

deleted by author

reply

to be fair, we spend a lot of time studying haha

reply

I'm impressed by that reasoning. I think I would have tried to calculate the meeting point.

reply

same here. I was stumped tbh.

I have to unlearn and relearn my Maths in order to prepare my children for the current realities of the Maths syllabus

reply

based on what?

reply

Don't know. I'd probably try to logic that out, and if not possible eventually maybe realize the trick.

In other words, I'd waste a lot of time brute forcing it before I'd stumble upon a more elegant solution.

reply

That’s what I started doing. Once I had it sketched out and parameterized, I realized that the intersection point could be anywhere in the middle box.

reply

Ah, I thought you took one look, saw that you weren't given enough information for the intersection, and reasoned the intersection could be anywhere, including on a straight line between the two corners.

reply

I did start out with an inclination that there was a cute simple answer like that, but I started working it out to make sure I wasn’t missing something.

reply